1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 | #!/bin/bash # LOCATION=$1 # cd $LOCATION hintStr=`echo "\033[37m *该功能实现的是 在指定文件夹下，批量重命名文件的名字* \033[0m"` echo $hintStr echo "【1】请输出要转换的文件夹路径:" read TARGET_PATH nullPath=`echo "\033[31m 空路径 ❌ \033[0m"` if [[ -z $TARGET_PATH ]]; then echo $nullPath exit 0 fi # LOCATION_FILES_NUM=`ls -l | grep "IMG" | wc -l ` CUREENPATH=`pwd` echo "【2】请输出重命名的文件名字(如 zhang)后面会自增123..:" read rename_name index=0 function rename() { # echo $FILES if [[ ! -e "$TARGET_PATH/rename_files" ]]; then mkdir "$TARGET_PATH/rename_files" fi for f in `ls $TARGET_PATH|tr " " "?"`; do # 空格问题 用？代替空格，然后在换过来 f=${f//'?'/' '} echo "------ $f" echo "++++++ $f" fileType=`echo ${f##*.}` if [[ $f == *.* ]]; then fileType=".$fileType" else fileType='' fi target_file=$TARGET_PATH/rename_files/"$rename_name""$fileType" if [[ -e $target_file ]]; then index=$[$index+1] target_file=$TARGET_PATH/rename_files/"$rename_name"$index"$fileType" fi mv "$TARGET_PATH/$f" "$target_file" done } rename |
使用方法：（dir_name：文件夹路径）
sh rename.sh
# 问题：
1. ls文件名有空格的问题
1 | for f in `ls $TARGET_PATH|tr " " "?"`; do |
首先用？代替空格，然后
1 | f=${f//'?'/' '} |
再转换为空格
